Math, asked by pravin3103, 1 year ago

Instructions:Find the odd man out.
Question:44,94,248,623,721

a) 94 
b) 248
c) 623
d) 721

Answers

Answered by roshinik1219
0

Given:

  • A series is given 44,94,248,623,721

To Find:

  • Find the odd man out in the given series.

Solution:

The given series is

            44,94,248,623,721

  • First check all the numbers

      ⇒     44 = 4 × 4 = 16              ⇒   1+6 = 7

      ⇒     94  =9 × 4 = 36              ⇒ 3 + 6 = 9

      ⇒     248  = 2 × 4 × 8 = 64    ⇒  6 +4 = 10

      ⇒      623  = 6 ×2 × 3 = 36    ⇒  3 +6 = 9

      ⇒      721  = 7 ×2 × 1 = 14      ⇒  1 +4 = 5

From the above pattern we can clearly see that all the numbers have odd digit at the end after doing some operation.  except one number and that number is 248.

Thus, The odd man out is 248

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