Question

int 2x/1+c^2 ×dx
fast​

Answer 1

Answer:

Q.

\int\frac{1}{2}dx - { \int\frac{1}{2}dx}∫

2

1

dx−∫

2

1

dx

Answer:-

Integrating with respect to dx

integration of adx is 'ax' where 'a' is constant

\int\frac{1x}{2}+C- { \int\frac{1x}{2}+C}=0∫

2

1x

+C−∫

2

1x

+C=0

1/2 is a constant term in given question

C is the constant of integration/anti derivative

Formula used

a\int{dx} =axa∫dx=ax

Answer 2

Hope it helps you........