Question

Int a = 2*3/ 2*5/ 2&1;

Answer 1

int a = 2*3/ 2*5/ 2;

int a = 6/2*5/ 2;

int a = 3*5/ 2;

int a = 15/ 2;

int a =7 // since a is integer type

Int a = 2*3/ 2*5/ 1;

Int a = 6/ 2*5/ 1;

Int a = 3*5/ 1;

Int a = 15/ 1;

Int a = 15;

Hope it HELPS

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Answer 2

Given: a = 2 * 3 / 2 * 5 / 2 & 1

According to the order of precedence,

• " * " an " / " has an equal precedent value, in this case, therefore, we would operate from left to right while performing the operations.
• " & " or bitwise AND has the lowest precedence.

Therefore,

a = 6 / 2 * 5 / 2 & 1

a = 3 * 5 / 2 & 1

a = 15 / 2 & 1

a = 7 & 1

a = 1

( Since any number other than 0 is TRUE or has the binary value 1, and        1 AND 1 is TRUE or has binary value 1 )