Question

int g (int x, int n) {
for (int i = 0; i < n; i++) {
if (i % 2 == 0) {
x *= i + 1;
continue;
}
x--;
if (x == 0) {
break;
}
}
return x;
}

What does g(1, 3) evaluate to?

Answer 1

Answer:

#include <stdio.h>

void main()

{

int a[3] = {1, 2, 3};

int *p = a;

printf("%p\t%p", p, a);

}

#include <stdio.h>

void main()

{

char *s = "hello";

char *p = s;

printf("%p\t%p", p, s);

}

1. include <stdio.h>

int main()

{

const int ary[4] = {1, 2, 3, 4};

int *p;

p = ary + 3;

*p = 5; //WONT COMPILE because const

printf("%d\n", ary[3]);

}

I hope this will helps you plz mark as brainliest answer and also like my answer plz