Question

Int i = 1; while(i++<=1) { i++; system.out.print(i + "" "" ); } system.out.print(i);

Answer 1

Answer:

Well the answer is 3 4

Explanation:

int i = 1;

while (i++<=1){...}

The while statements checks if 'i' is lesser or equal to 1...

now 'i' is 1, so the interpreter hops inside the loop.

But the while loop's condition has i++ in it, so 'i' gets incremented after the interpreter goes inside the loop.

'i' is now 2

i++; so 'i' is now 3

S.O.P(i + " "); displays "3 "

next the interpreter goes back to check the condition of the while loop.

while (i++<=1) {...}

as 'i' is 3, the condition is false, BUT the condition also contains the statement i++, so i gets incremented by 1, making 'i' as 4

After the loop ends,

S.O.P(i); display "4"

So the total result is "3 4"

Writing i++, the interpreter will first execute the current statement, then it will increment i by 1

I hope you understood my explanation, English is not my primary language.

Answer 2

Answer:

3 4

this is the answer

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