Question

int i=3;
printf("%d%d",i,i++);
what is output?

Answer 1

Answer:

43

Explanation:

II Its Solved questions

Answer 2

Answer:

The output of the code is 43.

Explanation:

int i=3;

printf("%d%d",i,i++);

• At first sight, it felt that the output of the code will be either 34 or 33. But both are incorrect.
• These kinds of codes are known as the exception code that doesn't give the output as we might think.
• Here we have an integer variable i with the value 3.
• Then we print the value of i and incrementation of i,
• In the second line, the value of i is incremented by one by the postfix operator so 3+1 =4, and 4 is printed.
• since the second format specifier wants to print i with the previous value. So 3 is printed.
• Hence, we get the output as 43.

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