Question

int main()
{
int n[ = {8, 1, 3, 9, 4);
intj, *y = n;
for(j=0; j<5; j++)
{
if(j%2==0)
*y++;
}
printf("%d", *y);
return 0;
}​

Answer 1

Explanation:

case 1: a = a-1;. } printf("%d \n",a); return 0;. } (a) 5. (b) 4. (c) 3. (d) None of these. 5 . ... int main(). { int i, j; for (i = 0; i <= 5; i ++) j = counter(i); printf("%d\n", j); return 0;. }

Answer 2

Answer:

int main()

{

int n[ = {8, 1, 3, 9, 4);

intj, *y = n;

for(j=0; j<5; j++)

{

if(j%2==0)

*y++;

}

printf("%d", *y);

return 0;

}