Computer Science, asked by sonalibaral85, 4 months ago

int num=3251;
int rev = 0;
while(num > 0) {
rev rev+num%10;
num/=10;
printf ("Output : "+rev);

Answers

Answered by mad210203
1

Program is given below.

Explanation:

The complete program is given below.

//This program is used to find the reverse of a number.

#include <stdio.h>

int main()

{

//Declaring the variables

int num=3251;

//We can take any number in place of 3251

int rev=0;

//Main code

//This code finds the reverse of the number

while(num>0)

{

rev=rev*10+num%10;

num/=10;

}

//This statement prints the reverse of the number

printf("Reverse of the given number is \n");

printf("Output: %d",rev);

return 0;

}

Refer the attached image for the output.

Attachments:
Answered by mayankmonu9
0

Answer:

the outside is rev is 11 so because number is greater so is 11

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