Question

int(sin4x-sin2x)/(cos x)dx`​

Answer 1

Solution :

Let I=∫

cos4-cos2x

sin4x-sin2x

dx= -2sin3xsinx2cos3xsinx

dx =∫sin3x cos3x dx

Let, cos3x=t⇒-3sin3xdx=dt

So, our integral becomes,

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