Question

int x = 1, y=1;
if(n>0)
{
x=x+1;
y=y+1;
}

what will be the value of x and y,if n assumes a value of (1) 1 and (2) 0 ?
plz answer​

Answer 1

If n = 1

1 > 0 Condition True 1 is greater than 0

x = 1 + 1

x = 2

y = 1 + 1

y = 2

If n = 0

0 > 0 Condition False

Comes out of the loop

No Output

Answer 2

Answer:

When n = 1 than the value of x = 2 and y = 2

When n = 0 ,value of x and y remain same .

Explanation:

Given ,

if(n > 0)

{

x = x + 1 ;

y = y +1 ;

}

If the value of n assumes to be 1 then ,

1 > 0 ,the condition is true .

So , its code  is executed adding 1 to both x and y.

int x= 1 ,y = 1;

if(1 > 0 )

{

x = 1 + 1

x= 2;

y = 1 +1

y = 2;

}

Output , (1) n = 1

x = 2 and y = 2 .

If the value of n assumes to be 0 then , condition is not satisfy .

Hence , When n = 1 then the condition is true and the value of x is 2 and y is also 2 . When n = 0, condition is false so x and y retain their original values.

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