Question

integer is given below random 10 to 100 find the probability of that is divisibke by 8 and 2nd part
not divisible by 8

Answer 1

Solution :
there are 91 integers between 10 and 100
now lets come to the first part
no. divisible by 8 are 16,24,32,40,48,56,64,72,80,88,96

now the probability is
P(divisible by 8) = 11/91

P(not divisible by 8) = 1-(11/91) = 80/91

Answer 2

Heya !!

Here is your answer..

Total number of integer between 10 to 100 is 91.

The numbers divisible by 8 are ==>

8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96

a). Probability of getting a number divisible by 8

==> 12/91

b) Probability of getting a number not divisible by 8

==> P ( not divisible by 8 ) = 1 - (11/91)

==> 80/91

Hope it helps.