Question

Integer p, q, r Set p= 3, q =1, r = 2 if(p+ (2&2&2) && q + (3&3&3) && r + (2^2^2)) p = p - 2 q = p Else p = r q = q ^ 2 End if Print p+ q+ r

Answer 1

Answer:

Integer a, b, c

Set a = 8, b = 6,c = 4

if(a > b)

a = b

Else

b = a

End if

if(c> b)

c = b

Else

b = c

End if

Print a + b + c

Answer 2

Answer:

The output of the given code will be 4.

Explanation:

• The first part of the code declares three variables named p, q, and r, and initializes them as p=3, q=1, and r=2.
• After initializing, an if-else loop is used to test the conditions.
• The condition first checks if p+(2&2&2) gives a logic high output. (2&2&2) means bitwise ANDing 2 with itself three times. ANDing any number with itself gives the number itself as the result.
• After the bitwise operation, the result is added to the value of p. If this yields a value greater than zero, then the output of the expression p+(2&2&2) gives a logic high output.
• Similarly, the expressions q + (3&3&3) and r + (2^2^2) are also executed and the outputs obtained are logic high.
• The outputs of these three expressions are logically ANDed meaning that if all three are logic high, then the if statement block will be executed.
• If even any one of the three expressions had logic low output, then the else statement block will be executed.
• Since, the outputs are logic high, the if statement block is executed.
• The value of p is subtracted by 2 and the new value assigned is p=1.
• The value of p is copied to q and the new value is q=1.
• The value of r remains unaltered r=2,
• The else statement block will not be executed.
• The values of p, q, and r are added together. Therefore, $p+q+r=1+1+2=4$
• This final value is then printed.

Therefore, the result of the program is 4.

#SPJ3