Question

Integer p,q,r Set p= 9,q= 5,r=7 r=4&q p= p^p if((q&r)

Answer 1

Answer:

p=0,q=5,r=4

Explanation:

as p&q is 5 it goes in to if loop

initially p=9,q=5,r=7

r=4&5 it is r=4 after bit wise AND

p=p^p it becomes zero

Answer 2

From the given question the correct answer is  

p=0,q=5,r=4

because

as p&q is 5 it goes in to if loop

initially p=9,q=5,r=7

r=4&5 it is r=4 after bit wise AND

p=p^p it becomes zero