Question

Integra of 6-2t.dt limits 0to 4​

Answer 1

Answer:

sorry it's not related to me

Answer 2

integration of 6 is 6t

and 2t is 2×t²/2 =t²

integration of 6-2t=6t-t² under limits 0 _ 4

substute 4 in that equation no need of 0 because the value will also become 0

so answer is 6×4-4²=24-16=8 is the correct answer hope this answer helpful