Integral 0 to pieby 2 mode sinx-cosx dx
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Answer:
Answer :
22–√−1)
Solution :
∫π/20|sinx−cosx|dx
=∫π/40−(sinx−cosx)dx+∫π/2π/4(sinx−cosx)dx
=|cosx+sinx|π/40+|−cosx−sinx|π/2π/4
=(12–√+12–√−1−0)+(−0−1+12–√+12–√)
=42–√−2=22–√−2
2(2–√−1)
Step-by-step explanation:
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