Question

Integral 0 to pieby 2 mode sinx-cosx dx

Answer 1

Answer:

Answer :

22–√−1)

Solution :

∫π/20|sinx−cosx|dx

=∫π/40−(sinx−cosx)dx+∫π/2π/4(sinx−cosx)dx

=|cosx+sinx|π/40+|−cosx−sinx|π/2π/4

=(12–√+12–√−1−0)+(−0−1+12–√+12–√)

=42–√−2=22–√−2

2(2–√−1)

Step-by-step explanation: