Question

integral 0 to π sin^6x cos^4x dx​

Answer 1

Step-by-step explanation:

We have,

$\int_{0}^{\pi} \sin^{6} (x) \cos ^{4} (x) dx$

$=2 \int_{0}^{ \frac{\pi}{2} } \sin ^{6} (x) \cos^{4} (x) dx$

$= 2 \times \frac{5 \times 3 \times 1 \times 3 \times 1}{10 \times 8 \times 6 \times 4 \times 2} \times \frac{\pi}{2}$

$= \frac{3\pi}{256}$