Question

integral[(1/109x)-1/(109x)^2 ]dx

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Answer 1

Answer:

$ans. \: \: I=</p><p> \sqrt{ } \frac{1 + 109x}{x.109x} dx \\ \\ = \sqrt{(} \frac{1}{109x2} + \frac{1}{x})dx \\ \\ = \frac{1}{109} \sqrt{} \frac{1}{x2} dx + \sqrt{} \frac{1}{x} dx \\ \\ = \frac{1}{109} ( - \frac{1}{x} ) + log \: x + c \\ \\ = - \frac{1}{109x} + log \: x \: + c.answer$

Step-by-step explanation:

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Answer 2

Refer to the above attachment...

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