Question

integral 1/xlogx dx please answer me​

Answer 1

Answer:

log(log)+c

Step-by-step explanation:

integral 1/xlogx dx. ........1

put z=logx

diff.w.r.t x

dz=1/x dx

from (1)

integral 1/z dz

log(z)

put the value of z

log(logx)