Question

integral (2x-3) (3x-2) dx​

Answer 1

Step-by-step explanation:

We have,

$\int(2x - 3)(3x - 2)dx$

$= \int(6 {x}^{2} - 9x - 4x + 6) dx$

$= \int6 {x}^{2} dx- \int9xdx - \int4x dx+ \int6dx$

$= 6\int {x}^{2} dx- 9\int \: xdx - 4 \int \: x dx+6 \int \: dx$

$= 6\ \frac{ {x}^{3} }{3} - 9\frac{ {x}^{2} }{2} - 4 \frac{x^{2} }{2} + 6x + C$

$= 2{x}^{3} - \frac{ 13}{2} {x}^{2} + 6x + C$