Question

integral(2x+3)/(x^2+3x+5)^6​

Answer 1

Answer:

$put \: {x}^{2} + 3x + 5 = y \\ 2x + 3 = \frac{dy}{dx} \\ (2x + 3)dx = dy \\ \\ so \: integrate \: \frac{dy}{ {y}^{6} } \\ integrate \: {y}^{ - 6} dy \\ \frac{ {y}^{ - 5} }{5} + c \\ \frac{ {( {x}^{2} + 3x + 5)}^{ - 5} }{ - 5} + c$

Answer 2

Answer:

this is correct..................................