integral dx/x √(6(log x)^(2)+7 log x+2 )
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Let I=∫1x(6ln2(x)+7ln(x)+2)dx
Lets assume ln(x)=y
⟹1xdx=dy
Now substituting the above values into I, we get,
I=∫16y2+7y+2dy
=∫16y2+4y+3y+2dy
=∫12y(3y+2)+3y+2dy
=∫1(2y+1)(3y+2)dy
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