integral dx/(x((x^2)+2))
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good question. that's your answer.
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abhi178:
you did mistake
Answered by
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∫dx/x(x² + 2)
Let (x² +2) = z
differentiate,
2x.dx = dz use this above ,
∫1/2dz/(z -2).z
⇒1/2.∫dz{1/z - 1/(z - 2)}(-1/2)
⇒-1/4.[∫dz/z -dz/(z-2)]
⇒-1/4[㏑z - ㏑(z-2)]
⇒1/4.㏑(z-2)/z
⇒1/4㏑x²/(x²+2)
Let (x² +2) = z
differentiate,
2x.dx = dz use this above ,
∫1/2dz/(z -2).z
⇒1/2.∫dz{1/z - 1/(z - 2)}(-1/2)
⇒-1/4.[∫dz/z -dz/(z-2)]
⇒-1/4[㏑z - ㏑(z-2)]
⇒1/4.㏑(z-2)/z
⇒1/4㏑x²/(x²+2)
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