Question

integral e^1/x^2/x^3

Answer 1

I = e^{1/x²}dx/x³
Let {1/x²} = P
differentiate both sides,
-1/x³ = dP/dx
dx/x³ = -dP , put this above

I = - e^P.dP
= -e^P + C
where C is constant.
now, put P = {1/x²}

I = - e^{1/x²} + C (answer )