integral e^2x +1 /e^2x -1 dx
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Given to find,
Consider the integral,
Multiplying both numerator and denominator by
Substitute,
Then (2) becomes,
Assume,
Then (3) becomes,
From (4),
Analysing each coefficient,
Solving them we get,
Then (5) becomes,
Undoing substitution
Then (1) becomes,
Taking
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Answer:
The value of integral is log|e^2x - 1| - x + c
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