Math, asked by uikeysonam27, 1 month ago

integral of (3x + 5)^4.dx​

Answers

Answered by Anonymous
2

Answer:

Let f(x) = 3x + 5

∫(3x + 5)4dx = (1/3)∫(3x + 5)4(3dx)

Now you have an integral of the form

∫f(x)ndf = f(x)n+1/(n + 1) + c

∫(3x + 5)4dx = (1/3)∫(3x + 5)4(3dx) = (1/3)(3x + 5)5/5 + c = (3x + 5)5/15 + c

Step-by-step explanation:

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Answered by Anonymous
1

Let f(x) = 3x + 5

 ∫(3x + 5)4dx = (1/3)∫(3x + 5)4(3dx)

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