Question

integral of (4-9x)^5.dx​

Answer 1

Answer:

answer is in attachment Hope you got it thanks

Answer 2

Answer: HelloMate!

Let (4–9x) = t

= > -9dx = dt

=> dx = -dt/9

integration ( t^5 ) .(-dt/9)

= t^6 /6 . (-1/9) + c

= - t^6 / 54 + c

= - ( 4–9x)^6 / 54 + c