integral of 7e^3x DX
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The answer is ∫e3xdx=e3x3 . So we have f(x)=e3x=g(h(x)) , where g(x)=ex and h(x)=3x . We know that the derivative of h(x)=3x is h'(x)=3 .
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integral of 7e^3x DX is 7/3 e^3x
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