Integral of cos2x + 2sin square x whole divides by cos square x dx. Please help
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Answer:
tan x + C
Step-by-step explanation:
cos 2x + 2 sin² x
= ( cos² x - sin² x ) + 2 sin² x
= cos² x + sin² x
= 1
So...
( cos 2x + 2 sin² x ) / cos² x
= 1 / cos² x
= sec² x
So...
∫ [ ( cos 2x + 2 sin² x ) / cos² x ] dx
= ∫ sec² x dx
= tan x + C
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