Question

Integral of Cos2x

Solve it.

Answer 1

$\textbf{Hey there}$!!

$\textbf{Solution}$:

$\int{cos2x.dx}$

We know that $\int{cosxdx}$ = sinx

Therefore,

I = $\frac{Sin2x}{2}$ + C

Where C is Arbitrary Constant.

#Be Brainly.

Answer 2

$\Large \tt {Solution:-}$

$\bf \int{cos2x.dx}$

$\bf We\: know \:that \:\int{cosxdx}=sin x$

$\bf I = \dfrac{Sin2x}{2} +C$