Physics, asked by cdrsreeram, 1 year ago

Integral of dx/root(2ax-x^2) =a^n Sin^01 [x/a -1]. Value of n using dimensional analysis is?

Answers

Answered by nanthitha18
1

Answer:

dx/√a(2as-x^2)

[a^2sin^-1(s/a-1)

a=0

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