Question

integral of e^-st×sin 2t×dt​

Answer 1

Answer:

1/8

Step-by-step explanation:

Let I=∫

0

π/4

sin

3

2tcos2t dt and let sin2t=u.

Then, d(sin2t)=du⇒2cos2t dt=du

⇒cos2tdt=

2

1

du

Also, t=0⇒u=sin0=0 and t=

4

π

⇒u=sin

2

π

=1

∴I=

2

1

∫

0

1

u

3

du

=

2

1

[

4

u

4

]

0

1

=

8

1

[u

4

]

0

1

=

8

1

(1−0)

=

8

1

Answer 2

Answer:

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Step-by-step explanation:

hope it help

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