Math, asked by rangaraomaruturi, 7 months ago

integral of ( logx)/x

Answers

Answered by Anonymous
62

Question :

Evaluate integral log x/x

Solution :

We have to integrate logx /x

\sf\int\dfrac{\log\:x}{x}

Let t = log x

Now Differentiate with respect to x

\sf\dfrac{dt}{dx}=\dfrac{1}{x}

\sf\:xdt=dx...(1)

Now ,

\sf\int\dfrac{\log\:x}{x}=\int\dfrac{t}{x}\times\:xdt

\sf=\int\:tdt

We know that

\rm\int\:x^n=\dfrac{x{}^{n+1}}{n+1}

\sf=\dfrac{t^2}{2}+c

\sf=\dfrac{(\log\:x)^2}{2}+c

Answered by vk8091624
2

Answer:

Evaluate the following integral: \[ \ int x \log x \, dx. \]. We use integration by parts, defining. \begin{align*} u &= \log x & du &= Then we ...

Similar questions