integral of root x+3
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Answered by
1
[tex] \int\limits x+3 dx
\int\limits x dx + \int\limits 3 dx [/tex]
x²/2+ 3x + c
hope it's help u
\int\limits x dx + \int\limits 3 dx [/tex]
x²/2+ 3x + c
hope it's help u
Answered by
0
∫√(x+3)dx=∫(x+3)^1/2 dx=(x+3)^1/2+1
_________
1/2+1
=(x+3)^3/2 + c
________
3/2
=2 (x+3)^3/2 + c
__________
3
_________
1/2+1
=(x+3)^3/2 + c
________
3/2
=2 (x+3)^3/2 + c
__________
3
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