Question

Integral of sec^2 (7-4x)

Answer 1

$\textbf{Hey there}$!!


$\textbf{Solution}$:


= ∫$sec^{2}}$( 7 - 4x ).dx.........( i )


Put 7 - 4x = t

So that,

-4dx = dt

dx = $\frac{-1}{4}$ .dt


Put value of dx in eq. ( i )


I = ∫ $\frac{-1}{4}$ $sec^{2}$.dt


I = $\frac{-1}{4}$ ∫ $sec^{2}$ .dt


I = $\frac{-1}{4}$ tan t + C



I = $\frac{-1}{4}$ tan ( 7 - 4x ) + C



#Be Brainly.

Answer 2

I am Aanya Kandwal.........