Question

Integral of secxdx find the part integral

Answer 1

Integral of secxdx

Integrating both sides, we get:

sec x dx = ln(sec x + tan x) + c.

Answer 2

Answer:

$→ \int \sec(x) dx = \int \ \frac{ \sec(x)( \sec(x) + \tan(x)) }{( \sec(x) + \tan(x)) }dx\\(multiplying\: numerator\: and\: denominator\:by\:(sec(x)+tan(x)) \\ Now\:let \: ( \sec(x) + \tan(x) ) = t \\ \sec(x) ( \sec(x) + \tan(x) )dx = dt \\ \int \frac{dt}{t} = log |t| + C \\ = log |( \sec(x) + \tan(x) | + C$

• log|(sec(x)+tan(x)|+C is the right answer.