Question

Integral of sin 4x cos 3x dx

Answer 1

[tex]\int \sin 4x\cos 3x dx\\ = (1/2) \int (\sin 7x + \sin x )dx\\ =(1/2) [ -\cos 7x/7 -\cos x] + c\\ =-(\cos7x) / 14 -( \cos x) / 2 + c[/tex]