Question

Integral of (sinx/(1+cosx)^2 ).dx

Answer 1

$\textbf{Hey there}$!!


$\textbf{Check The Attachment}$⬆⬆⬆


Be Brainly.


@karangrover12.

Answer 2

Hello!

$\int \dfrac{\sf sinx}{\sf (1+cosx)^{2}} \sf dx \\ \\ \implies - \sf sinx\:dx = \sf dt \\ \\ \implies \sf sinx\:dx = \sf -dt \\ \\ \implies \int - \dfrac{\sf dt}{\sf t^{2}} \\ \\ \implies - \int \dfrac{1}{\sf t^{2}} \sf dt \\ \\ \implies - \int \sf t^{-2} \:dt \\ \\ \implies \sf t^{-1} + \sf C \\ \\ \implies \dfrac{1}{\sf t} + \sf C \implies \boxed{\red{\bf{\dfrac{1}{\sf 1+cosx} + \sf C}}}$

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