Question

integral of (tan^3x-xtan^2x)dx​

Answer 1

Answer:

P

Step-by-step explanation:

Answer 2

here's your answer

Integrate the following w.r.t. x (tan3x - xtan2x)

∫tan3x - xtan2x. dx

∫tan2x (tan x - x).dx

∫sec2x - 1(tan x - x).dx

∫sec2x.tan x.dx - ∫x.sec2x.dx - ∫tan x.dx + ∫x.dx

Let tanx = t then sec2x.dx = dt .

then break u.v in ∫x.sec2x.dx

directly

(tan2x)/2 - xtanx + ∫tan x.dx - ∫tan x.dx + (x2)/2

(tan2x)/2 - xtanx +(x²)/2

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