Question

integral of tan square x ​

Answer 1

Recall that sec2x=tan2+1 and that ∫sec2x=tanx+C

So tan2x=sec2x−1

=> ∫tan2x dx = ∫(sec2x−1) dx

=∫sec2x dx−∫1 dx

=tanx−x+D

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Answer 2

solutions is above......