integral of [x+½]³
w.r.t x
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Answer:
x³ + 3x²/2 + 3x/4 + 64
Step-by-step explanation:
I hope u mean simplify.
We use the formula, (a + b)³ = a³ + 3a²b + 3ab² + b³
= (x + 1/2)³
= x³ + 3x²/2 + 3x/4 + 64
I hope this is what you want. Would be great if you gave brainliest.
:)
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