Question

integral root cot X dx​

Answer 1

Answer:

Sin x

Cos x

=

Sin x Cos x

Cos x Cos x

=

2

Sin 2x

Cos x

Let Sin 2x=t

2

, 2 Cos 2x dx=2t dt, (Cos

2

x−sin

2

x)dx=t dt

2

Sin 2x

Cos x

dx=

2t(Cos x+sin x)(Cos x−Sin x)

Cos x t dt

=

=

4(Cos x+Sin x)

dt

+

4(Cos x−Sin x)

dt

=

4

(Cos x+Sin x)

2

dt

+

4

(Cos x−Sin x)

2

dt

=