integral Root of 1+sinx dx
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putting 1 = sin square x by 2 + cos square x by 2
and sinx= 2sin x by2 cos x by 2
then we get formula as (a+b) ka holl square = a square + b square +2ab
solving we get integral of sin x by 2 + cos x by 2 dx
then do sin x by 2 and cos x by 2 ke integrals
2sinx/2 - 2cos x/2 + c ans
SUMIT GUJJAR
and sinx= 2sin x by2 cos x by 2
then we get formula as (a+b) ka holl square = a square + b square +2ab
solving we get integral of sin x by 2 + cos x by 2 dx
then do sin x by 2 and cos x by 2 ke integrals
2sinx/2 - 2cos x/2 + c ans
SUMIT GUJJAR
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