integral(sin^2x +cos^4x dx)
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∫
s
i
n
2
x
c
o
s
4
x
d
x
∫sin2xcos4xdx
∫
(
1
−
c
o
s
2
x
)
(
c
o
s
4
x
)
∫(1−cos2x)(cos4x)
∫
(
c
o
s
4
x
−
c
o
s
6
x
)
d
x
∫(cos4x−cos6x)dx
cos
2
x
=
1
+
cos
2
x
2
cos2x=1+cos2x2
1
2
∫
c
o
s
4
x
d
x
−
1
2
∫
c
o
s
6
x
d
x
12∫cos4xdx−12∫cos6xdx
1
8
∫
(
1
+
c
o
s
2
x
)
2
−
1
16
∫
(
1
+
c
o
s
2
x
)
3
18∫(1+cos2x)2−116∫(1+cos2x)3
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