Integral substitution method for e^tan-1xdx\1+x^2
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take tan^-1x = y
diffentiating we get (1/1+x^2)dx = dy
now substituting these values we get
integral of e^y.dy = e^y
= e^tan^-1x
hence this is the required answer
diffentiating we get (1/1+x^2)dx = dy
now substituting these values we get
integral of e^y.dy = e^y
= e^tan^-1x
hence this is the required answer
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