Integral zero of x^3+6x^2+11x+6
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Now,
x³ + 6x² + 11x + 6
= x³ + x² + 5x² + 5x + 6x + 6
= x² (x + 1) + 5x (x + 1) + 6 (x + 1)
= (x + 1) (x^2 + 5x + 6)
= (x + 1) (x^2 + 3x + 2x + 6)
= (x + 1) {x (x + 3) + 2 (x + 3)}
= (x + 1) (x + 3) (x + 2)
Hence, the integral zeroes of the given polynomial are
(- 1), (- 2) and (- 3).
#MarkAsBrainliest
Now,
x³ + 6x² + 11x + 6
= x³ + x² + 5x² + 5x + 6x + 6
= x² (x + 1) + 5x (x + 1) + 6 (x + 1)
= (x + 1) (x^2 + 5x + 6)
= (x + 1) (x^2 + 3x + 2x + 6)
= (x + 1) {x (x + 3) + 2 (x + 3)}
= (x + 1) (x + 3) (x + 2)
Hence, the integral zeroes of the given polynomial are
(- 1), (- 2) and (- 3).
#MarkAsBrainliest
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