Integrals.
Simple.
Please tell.
Ayyyy
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Answer:
logt + C
Step-by-step explanation:
To find ----> ∫ dt / t
Solution----> We know that,
∫ xⁿ dx = xⁿ⁺¹ / ( n + 1 ) + c
But this formula is not applied for n = -1
We know that ,
d / dx ( log x ) = 1 / x
= x⁻¹
So intregation of ( x⁻¹ ) is logx , So,
∫ 1 / x dx = log x + C , where C is constat of intregation.
Now , ∫ dt / t = log t + C
Additional information---->
1) ∫ xⁿ dx = xⁿ⁺¹ / ( n + 1 ) + C
2) ∫ eˣ dx = eˣ + C
3) ∫ aˣ dx = aˣ / loga + C
4) ∫ Sinx dx = - Cosx + C
5) ∫ Cosx dx = Sinx + C
6) ∫ Sec²x dx = tanx + C
7) ∫ Secx tanx dx = Secx + C
8) ∫ Cosecx Cotx dx = - Cosecx + C
9) ∫ Cosec²x dx = - Cotx + C
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