Question

Integrat this Equation

$-\frac{dI}{I} = K^{///} Cdb$

answere is $-log\frac{I}{I_o} = \frac{ K^{///}}{2.303} Cb$

Explain kre kese aya ye answere

Answer 1

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refer to the attachment

Answer 2

Answer:

Given:

A differential equation has been provided.

dI/I = K''' × C(db)

To find:

Integrated form of the differential equation.

-log(I/I°) = K'''/(2.303) × Cb

Calculation:

dI/I = K''' × C(db)

=> ∫dI/I = K''' × C × ∫db

Limits on LHS is from I° to I

Limits on RHS is from 0 to b

=> ln(I) - ln(I°) = K''' × C [ b - 0 ]

=> ln(I/I°) = K''' Cb

=> (2.303) × log(I/I°) = K''' Cb.

=> log(I/I°) = K'''/(2.303) × Cb .