Question

Integrate 1/ 1+cos3x dx

Answer 1

Answer:

1/1+sin3x..... follow me

Answer 2

Answer:

1−cos3x3sin3+c

Step-by-step explanation:

11=cos3x=12cos2(32x)

=12sec2(32x)

∫11+cos3xdx=∫12⋅secc2(32x)dx

=12∫sec2(32x)dx

=12*(23)tan(32x)+c

=13tan(32x)+c

=13sin(32x)cos(32x)+c

=13⋅sin2(32x)sin(32x)cos(32x)+c

=13⋅2sin2(32x)2sin(32x)cos(32x)+c

=13⋅1−cos3xsin3x+c

=1−cos3x3sin3+c

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