Question

Integrate - 1/√1+x^2 dx​

Answer 1

Answer:

Sorry I didn't know the answer

sorry for interrupting

Answer 2

Answer:

Step-by-step explanation:

The integral of 1 over the square root of 1−x2 is of the form ∫1√1–x2dx=sin–1x+c. To prove this formula, consider ddx[sin–1x+c]=ddxsin–1x+ddxc.