Integrate 1/(1+x2) for limit [0,1].
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Step-by-step explanation:
answer is 45° or π/4
because it's a simple formula
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Answered by
1
Step-by-step explanation:
let it given that
1/(1+x^2) limit for [0,1]
then
the integral of 1/(1+x^2) is
tan inverse x
[ 1/( a^2+ x^2) is 1/ a tan inverse
x/ a]
so now put the limit
tan inverse (1) - tan inverse (0)
the answer is
pi/4
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